贴代码，求合作

想做一个自动填数独的程序，已经写好C++程序了，哪位大佬能帮忙改成Scr的

#include <bits/stdc++.h>

using namespace std;

int a[21][21] = {0};

int n = 0;

int nulx[101] = {0};

int nuly[101] = {0};

bool p1[21][21] = {0};

bool p2[21][21] = {0};

bool p3[11][11][21] = {0};

int get(int);

void scan();

void save();

void solve(int);

void print();

void scan() {

for (int i = 1; i <= 9; i++) {
	for (int j = 1; j <= 9; j++) {
		scanf("%d", &a[i][j]);
		if (a[i][j] == 0) {
			n++;
			nulx[n] = i;
			nuly[n] = j;
		}
	}
}

}

void save() {

for (int i = 1; i <= 9; i++) {
	for (int j = 1; j <= 9; j++) {
		p1[i][a[i][j]] = 1;
	}
}
for (int j = 1; j <= 9; j++) {
	for (int i = 1; i <= 9; i++) {
		p2[j][a[i][j]] = 1;
	}
} 
for (int i = 1; i <= 3; i++) {
	for (int j = 1; j <= 3; j++) {
		for (int x = 1; x <= 3; x++) {
			for (int y = 1; y <= 3; y++) {
				p3[i][j][a[x + 3 * (i - 1)][y + 3 * (j - 1)]] = 1;
			}
		}
	}
}

}

int get(int k) {

if (k <= 3) return 1;
else if (k <= 6) return 2;
else return 3;

}

void print() {

printf("Answer:\n");
for (int i = 1; i <= 9; i++) {
	for (int j = 1; j <= 9; j++) {
		printf("%d ", a[i][j]);
	}
	printf("\n");
}
return ;

}

void solve(int k) {

if (k == n + 1) print();
else for (int i = 1; i <= 9; i++) {
	if (!p1[nulx[k]][i] && !p2[nuly[k]][i] && !p3[get(nulx[k])][get(nuly[k])][i]) {
		a[nulx[k]][nuly[k]] = i;
		p1[nulx[k]][i] = 1;
		p2[nuly[k]][i] = 1;
		p3[get(nulx[k])][get(nuly[k])][i] = 1;
		solve(k + 1);
		a[nulx[k]][nuly[k]] = 0;
		p1[nulx[k]][i] = 0;
		p2[nuly[k]][i] = 0;
		p3[get(nulx[k])][get(nuly[k])][i] = 0;
	}
}

}

int main() {

scan();
save();
solve(1); 
system("pause"); 
return 0;

}

（不想整理了，应该能跑）